y=sqrtx/(x+7) find equation of the tangent line at (9,3/16) and the equation of the normal line at (9,3/16)

Question

wolfe8 · Answer

What can be said about the derivative of a curve at a point with its tangent line?

anonymous · Answer

not sure

anonymous · Answer

@zepdrix

zepdrix · Answer

So we can write the tangent line as,$$\Large y-y_o\quad=\quad m(x-x_o)$$

Where our given point is $\Large (x_o,\;y_o)\quad=\quad (9,\; 3/16)$

And where $\Large m$ is given by derivative function evaluated at x=9.
$\Large f'(9)=m$

zepdrix · Answer

Have you tried taking the derivative of your function yet?

anonymous · Answer

yes i got (7-x)/2sqrtx(x+7)^2

anonymous · Answer

i was having trouble with the normal line equation. i dont get what that means

zepdrix · Answer

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