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Mathematics 14 Online
OpenStudy (anonymous):

y=sqrtx/(x+7) find equation of the tangent line at (9,3/16) and the equation of the normal line at (9,3/16)

OpenStudy (wolfe8):

What can be said about the derivative of a curve at a point with its tangent line?

OpenStudy (anonymous):

not sure

OpenStudy (anonymous):

@zepdrix

zepdrix (zepdrix):

So we can write the tangent line as,\[\Large y-y_o\quad=\quad m(x-x_o)\] Where our given point is \(\Large (x_o,\;y_o)\quad=\quad (9,\; 3/16)\) And where \(\Large m\) is given by derivative function evaluated at x=9. \(\Large f'(9)=m\)

zepdrix (zepdrix):

Have you tried taking the derivative of your function yet?

OpenStudy (anonymous):

yes i got (7-x)/2sqrtx(x+7)^2

OpenStudy (anonymous):

i was having trouble with the normal line equation. i dont get what that means

zepdrix (zepdrix):

|dw:1381600620258:dw|

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