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confirm f and g are inverserves: f(x)= x+3/4 and g(x)= 4x-3
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Plug them into each other.
So: \[\LARGE f(g(x))=\frac{(4x-3)+3}{4}\] So solve this and what do you get?
that denominator of 4 only goes over the 3 no?
x + 3/4 (4x-3) + 3/4
it's not clear the way it is written
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@feltznic000 is it x+(3/4) or (x+3)/4?
How do you get that?
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