Question

Would F(x) = 0 Mean the parabola has no zeros x-intercepts?

I had this in my notes but maybe I made a mistake

Answer 1

hey can u elaborate a bit... not getting wat u mean..

Answer 2

@ganeshie8

Answer 3

good thing to ponder on :)

see that the parabola is FLOATING up above the x axis,
that means it never touches/cuts x-axis. so there are no real zeroes for this guy

Answer 4

f(x) = ax^2+bx+c

we say
f(x) has no real zeroes, or f(x) = 0 has no real solutions

Answer 5

now tell me, wats ur exact question ? :)

Answer 6

that was the question and then when it has one x-intercept then it should be f(x)=1 right?

Answer 7

nope. its not that simple at all.

Answer 8

take below parabola :-

\(f(x) = 2x^2 + 3x + 3\)

Answer 9

tell me, how u wil find its x-intercepts/zeroes ?

Answer 10

I can use the quadratic formula or factor

Answer 11

x-intercepts occur, when y = 0, that is when function equals 0.

so we wil set f(x) = 0, and solve x to find x-intercepts :-

\(f(x) = 0\)
\(2x^2+3x+3 = 0\)

u can solve it by factoring/quadratic formula

Answer 12

^exactly

Answer 13

So it does not necessairly =1 but any number?

Answer 14

but what about one that has two x-intercepts

Answer 15

y = 30000

will not have 30000 intercepts ok

Answer 16

there is a method to knw how many intercepts a parabola can have :-
a parabola can have 0 or 1 or 2 x-intercepts

Answer 17

Yea its by the descriminats

I understand

thanks for the help

Answer 18

yup ! D = 0, means oly 1 xintercept/zero
D > 0, means 2 x-intercepts/zeroes
D < 0, means 0 real zeroes

Answer 19

np :)