Question

Hi I am new, and need help in a quadratic question can anyone help me ?

Answer 1

ya what do you need?

Answer 2

Can you show me the steps of how to solve quadratics?

Answer 3

ax^2 + bx + c = 0
you plug in (a,b, and c)
into the quadratic equation to find the solutions
\[x = \frac{ -b \pm \sqrt{b^2 - 4(a)(c)} }{ 2a }\]

Answer 4

show me how to find the solutions, in order to find them, what are the steps ?

Answer 5

It's just plugging in. Very simple, give a question so I can show you have it's done.

Answer 6

y=2x^2+3x+c

Answer 7

What is the value for c?.

Answer 8

how would you solve that ? and plus i made this equation up. I'm not looking for a spefic answer, i just wanna learn the quadratics

Answer 9

Does c not have a value?

Answer 10

does it have to have a value ?

Answer 11

Yes, it does.

Answer 12

if it does, then let c= -3

Answer 13

a = 2
b=3
c = -3

Answer 14

Now plug into the equation.

Answer 15

y=2x^2+3x+-3

Answer 16

Plug those into the quadratic equation you get
\[x = \frac{ -3\pm \sqrt{3)^2-4(2)(-3)} }{ 2(2) }\]

Answer 17

\[x = \frac{ -3\pm \sqrt{9+24} }{ 4 }\]

Answer 18

x = -3 +- √36 / 4
x = -3 + 6 / 4, x = -3 - 6 /4

x = 3/4
x= -9/4

Answer 19

Shamil show don't know that square root it confuses me. Tell me what difference does it make that the quadratic formula which is y=x^2+bx+c

Answer 20

y=x^2 + bx + c
is not the quadratic formula

Answer 21

That is used for graphic quadratic functions.

Answer 22

What ??

Answer 23

graphing*

Answer 24

ohhh for graphing only? no wonder, well show me how the square root one works

Answer 25

http://www.purplemath.com/modules/grphquad.htm

Read this page carefully it will explain how to graph quadratic functions..

Answer 26

But it's not the same as someone explaing it..