Question

Suppose an astronaut drops a feather from 1.2 m above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.62 m/s2 downward, how long does it take the feather to hit the Moon’s surface?

Answer 1

Hi. You can get the equation you need if you rearrange this one to solve for time. h = vt-0.5g(t)^2

Answer 2

But don't worry about the 'vt' part because I am assuming your initial velocity is zero. So the equation is just 'h = -0.5g(t)^2'.

Answer 3

Sorry, not -0.5, +0.5