If -3 <_ x <_ -1, determine a and b for the inequality: a <_ 6 - 2x < b I'm totally unsure how a question like this works, considering I need to flip the inequalities to get the "-2x" part of the question.
Multiply everything by -2 then add 6
The flipping of the sign doesn't matter, it just means that your a and b are on different sides
\[-3*-2\ge-2x \ge-1*-2\] \[12\ge6-2x \ge8\]
So your a is 8 and b is 12
Ah, okay, thanks.
What about the < vs. the <_? The answer you gave had two "greater than or equal" signs, shouldn't there be a "greater than" sign in there, a reflection of the "<" in the initial question?
Oh yes I missed that. Signs shouldn't usually change mid equation but if it's smaller or equal to 12, then it must be smaller than anything larger than 12, so I guess you could write that
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