Which of the following is/are the correct statement(s)?? 1.It is possible to have a situation in which the speed of a particle is always zero but the average speed is not zero. 2.It is possible to have a situation in which the speed of a particle is never zero but the average speed in an interval is zero. 3.If the position and velocity have opposite signs,the particle is moving towards the origin. Please provide detailed explanations!!
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here's the answer for option one: average(avg.) speed is nothing but total distance divided by total time. So, the first option says that a particle can travel some distance without some speed. If the object is at rest i.e. its speed is zero, it cannot travel any distance so the avg. speed will also become zero. for option two: okay the second option says that in a given time interval, speed can never be zero but avg. speed(total distance travelled in unit time) can be zero. This can never happen as the object has some speed, so, it will travel for some distance, and distance can never be equal to zero so avg. speed also cannot be equal to zero . So the second option is also wrong. Let's go to the third option. for the third option: the third option says that if the position and velocity vectors have opposite sign, then the particle is directed towards the origin. Let us look at this optionby using the cartesian plane.|dw:1381668593389:dw| now let v be the velocity vector and r be the position vector . so the positon of the object is 2i^+2j^ and the velocity is towards the left side so we can take it as -ve so imagine that the object is moving in that plane, so the object will approach the y axis so we can say that its distance rom the origin is decreasing and therefore it is moving towards the origin. if you have any doubts in the answer , feel free to ask
|dw:1381669350596:dw|
Ta...Really helpful!!.Any suggested sites for this type questions??????????
if you wanna practice physics, you may surely visit thephysicsclassroom.com and 'll keep you updated if i get something new
Ta mate!!:)
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