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2q/(2q+3) - 2q/(2q-3) = 1
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solve for q?
yes
oopes, messed all that up right quick
\[\frac{2q ( 2q - 3)- 2q (2q+3)}{(2q-3)(2q+3)} =1\] \[\frac {2q ((2q - 3) - (2q +3))}{ 4q^{2} - 9}=1\]
does that help at all / do you see where that comes from?
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yes I understand so far
Can you simplify that further?
I believe so. thank you for your help!
:) welcome
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