Question

$ln(cosx)dx

Answer 1

What?

Answer 2

it might be an exchange rate :)

Answer 3

I think \(\int \ln(\cos x)\,dx\)

Answer 4

we use log in exchange rATE>????

Answer 5

ever since the us got demoted to AA status, yes lol

Answer 6

the wolf is speaking greek on this one ...

Answer 7

hw in toilet abbot??

Answer 8

@abb0t curious to know...-_<

Answer 9

m out.....arivederchi..........sayonara..........aloha and 280 other sign outs

Answer 10

\[\Large \int\limits\ln(\cos x)\;dx\]
Let's try letting:\[\Large\bf u=\ln(\cos x), \qquad \qquad dv=dx\]Then,\[\Large\bf du=-\tan x\;dx,\qquad\qquad v=x\]

So integration-by-parts will give us:\[\Large\bf x \ln(\cos x)+\int\limits x \tan x\;dx\]
But then to deal with this new integral, hmmm..
Ya I think we have a problem :\
weird :c