How to write an equation of a line that passes through (4,3) and (-8,6)

Question

amistre64 · Answer

define the slope of the line between the given points, and use it to construct the point slope form of the line.

jigglypuff314 · Answer

$$slope = \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }$$

amistre64 · Answer

y = m(x-xo) + yo

texaschic101 · Answer

first you need to find the slope by using the slope formula
slope(m) = (y2 - y1) / (x2 - x1)
(4,3)  x1 = 4 and y1 = 3
(-8,6)  x2 = -8 and y2 = 6
now sub in your info into the formula...
m = (y2 - y1) / (x2 - x1)
m = (6 - 3) / (-8 - 4)

can you continue and find the slope from here ?

texaschic101 · Answer

Once you have the slope, you will use point slope formula...
y - y1 = m(x - x1)
slope(m) = (whatever answer you got for the slope)
and you can use either set of points...
(4,3) x1 = 4 and y1 = 3 or (-8,6) x1 = -8 and y1 = 6
pick ONE of those sets of points
now just sub your info into the formula.

Once that is done, solve for y and that will be your equation. It will be in y = mx + b form.

anonymous · Answer

thanks you guys!