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Mathematics 15 Online
OpenStudy (anonymous):

Find x in these 30 - 60 - 90 triangles. X=?

OpenStudy (anonymous):

OpenStudy (anonymous):

\[\sqrt{?}\]

jigglypuff314 (jigglypuff314):

understand that |dw:1381686907010:dw|

OpenStudy (anonymous):

yes

jigglypuff314 (jigglypuff314):

so x√3 = 7

OpenStudy (anonymous):

is that the final answer?

jigglypuff314 (jigglypuff314):

find x from that

jigglypuff314 (jigglypuff314):

so x = 7/(√3)

OpenStudy (anonymous):

why?

jigglypuff314 (jigglypuff314):

to get x from x(√3) = 7 divide both sides by (√3)

OpenStudy (anonymous):

oh okay now I understand

OpenStudy (anonymous):

how would you find Y?

jigglypuff314 (jigglypuff314):

now that you know that x = 7/(√3) y = 2x = 2(7/(√3)) = 14/(√3)

OpenStudy (anonymous):

thank u so much I understand when you explain it

jigglypuff314 (jigglypuff314):

your welcome :)

OpenStudy (anonymous):

Find x in these 45 - 45 - 90 triangles. x=?

jigglypuff314 (jigglypuff314):

understand that |dw:1381687738523:dw|

OpenStudy (anonymous):

yes

jigglypuff314 (jigglypuff314):

so 8 = x(√2)

jigglypuff314 (jigglypuff314):

then find x by dividing both sides by (√2)

OpenStudy (anonymous):

\[8/\sqrt{2}\]

jigglypuff314 (jigglypuff314):

yes :)

OpenStudy (anonymous):

my teacher confuses me but with you I'm catching on

OpenStudy (anonymous):

Solve these proportions. x=

jigglypuff314 (jigglypuff314):

miltiply both sides by (x/1)

OpenStudy (anonymous):

once I do that what would I do next

jigglypuff314 (jigglypuff314):

multiply both sides by 4

jigglypuff314 (jigglypuff314):

then square root both sides

OpenStudy (anonymous):

\[4\sqrt{3}\]

jigglypuff314 (jigglypuff314):

close... √12 = √(4*3) = √4 * √3 = 2√3

OpenStudy (anonymous):

Enter the trigonometric equation (sin, tan, or cos) you would use to find x in the following right triangles. Do not solve the equations.

jigglypuff314 (jigglypuff314):

understand that when |dw:1381689456194:dw| sin(x)= (opposite/hypotenuse) cos(x) = (adjacent/hypotenuse) tan(x) = (opposite/adjacent)

OpenStudy (anonymous):

yes

jigglypuff314 (jigglypuff314):

the question asks to find the length of the side opposite of the angle 70 and also gives you the value of the hypotenuse of the right triangle. so what sin, cos, or tan equation should you use given the opposite and hypotenuse?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

sin

jigglypuff314 (jigglypuff314):

correct :)

OpenStudy (anonymous):

how do you use the equation

jigglypuff314 (jigglypuff314):

to use it in context of the problem, sin(70)=x/8 then multiply both sides by 8 to get x alone

OpenStudy (anonymous):

Find x in this 45°-45°-90° triangle. x=

jigglypuff314 (jigglypuff314):

understand that |dw:1381691067571:dw|

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