Question

in triangle ABC, A=32 degrees, a=8, and b=7. Find C.

A. 110.7 degrees
B. 20.7 degrees
C. 30.4 degrees
D. 120.4 degrees

Answer 1

hey @Acenator15 , welcome to OS man, standby will draw a pic: easier then

Answer 2

to solve , either use Sine Rule
\[\frac {a}{\sin A} = \frac {b}{\sin B} = \frac {c}{\sin C}\]
then triangle rule (sum of all internal angles in a triangle = 180 degrees

or use Cos Rule
\[a^2 = b^2 + c^2 -(2bc \times \cos A)\]

Answer 3

ur choice...

Answer 4

let me know how u go @Acenator15

Answer 5

sine

Answer 6

Are you there

Answer 7

http://openstudy.com/study#/updates/4fff2465e4b09082c070512f
this is the same question may this help you...

Answer 8

It kind of helped me but they never gave an exact answer so I was stuck

Answer 9

sorry dude, teach a man to fish VS give a man a fish...
I'll help u with the solution, not give u the answers

Answer 10

so what should I do

Answer 11

so check out the picture i drew above...
you've got small a , small b and Large A
use the sine rule to find Large B (the angle which is opposite side small b)

then you'll have angle A and angle B

now for every triangle ever, the sum of all the internal angles is 180 degrees
so A + B + C = 180

so to find angle C, if you'll know sum of all of the angles = 180 and A = 32 and B = whatever u worked out above
so A + B + C = 180
therefore
C = 180 - (A + B)

:
so then you'll know: A, B , C, a, and b ... so use Sine Rule again to find c