Question

@ganeshie8 Hey again XD I started off doing this problem and I'm confused on how to finish it..

Answer 1

I multiplied like terms, yada yada yada so now I have
12\[12\sqrt{224x ^{10}y ^{8}}\]

Answer 2

\(\large 12\sqrt{224x ^{10}y ^{8}} \)

Answer 3

\(\large 12 \sqrt {16 \times 14 x ^{10}y ^{8}} \)

Answer 4

\(\large 12 \sqrt {4^2\times 14 x ^{10}y ^{8}} \)

Answer 5

\(\large 12 \sqrt {4^2\times 14 (x ^{5})^2(y ^{4})^2} \)

Answer 6

fine so far ? :)

Answer 7

Yes!:D

Answer 8

\(\large 12 \sqrt {14 (4x ^{5}y^4)^2} \)

Answer 9

wat about now ?

Answer 10

ive just grouped all square terms under one umbrella :)

Answer 11

Ooh I get it, I couldn't figure out what happened to the 16 but 4^2 equals 16:3 :D I get it! Do we do anything to the 12 or is that coming up?

Answer 12

good :)

that square term inside radical, we can pull out
\(\large 12 \times 4x^5y^4 \sqrt {14} \)

Answer 13

\(\large 48x^5y^4 \sqrt {14}\)

Answer 14

thats the final simplificaiton we can do

Answer 15

So wait, if we were to do this backwards, would be square the 14 or just multiply it by everything and everything gets square rooted? (This has confused me for a while so I thought I'd just ask now)

Answer 16

good question :)

Answer 17

(also, what happened to the ()^2 for the exponents?)