ok so i got -10 on the left side and 1 over -14 on the right side what do i do next
jigglypuff314 (jigglypuff314):
no, f(g(-6)) means to plug in -6 into the function of g(x) and take what you got from that, and plug that into the function of f(x)
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jigglypuff314 (jigglypuff314):
so you plug in 1 over -14 into f(x)
OpenStudy (anonymous):
this is confusing @jigglypuff314
jigglypuff314 (jigglypuff314):
g(-6) means to plug in -6 into the function of g(x)
f (g(-6)) means to plug in what g(-6) equals into the function of f(x)
OpenStudy (anonymous):
>.< can you please like write out the problem for me step by step
jigglypuff314 (jigglypuff314):
\[g(x) = \frac{ 1 }{ 2x-2 } \rightarrow g(-6)=\frac{ 1 }{ 2(-6)-2 }\] do you understand this so far?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
you plugged in the -6
jigglypuff314 (jigglypuff314):
then you simplify that
OpenStudy (anonymous):
do i multiply 2 and negative 6
jigglypuff314 (jigglypuff314):
yes
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OpenStudy (anonymous):
and then - 12-2
OpenStudy (anonymous):
is it 1 over negative 14
jigglypuff314 (jigglypuff314):
yes :)
OpenStudy (anonymous):
thats it?
jigglypuff314 (jigglypuff314):
then you plug 1 over 14 into x-4
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OpenStudy (anonymous):
how do i do that
jigglypuff314 (jigglypuff314):
so 1/14 - 4
OpenStudy (anonymous):
14-4
jigglypuff314 (jigglypuff314):
no, (1 over -14) - 4
OpenStudy (anonymous):
i multiply - 4
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jigglypuff314 (jigglypuff314):
no, 4 = 56 over 14
so 1 over negative 14 minus 56 over 14
OpenStudy (anonymous):
ho do i solve that
OpenStudy (anonymous):
55over -28
jigglypuff314 (jigglypuff314):
no, negative number minus number equals negative added numbers
and when adding fractions (or numbers over numbers) you don't add the bottom two numbers.
OpenStudy (anonymous):
so 55 over 14?
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jigglypuff314 (jigglypuff314):
-1-56 = -57
so your answer is negative 57 over 14
OpenStudy (anonymous):
thats not right
jigglypuff314 (jigglypuff314):
how is it not?
OpenStudy (anonymous):
my choices are 9
3
−9
−3
OpenStudy (anonymous):
soo ?
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jigglypuff314 (jigglypuff314):
hmm. i don't know...
OpenStudy (anonymous):
:o
OpenStudy (anonymous):
come on! your a pokemon!
OpenStudy (anonymous):
help!! we been on this question for 33 minutes i really need someone to help me
OpenStudy (anonymous):
@jigglypuff314
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