find all solutions to cos(2x)=cosx
Replace cos(2x) with 2cos^2x-1
Hint: Use the double-angle formula for cos(2x) = 2 cos^2 (x) - 1
Set all equal to zero, and factor that quadratic....
Wow!! Wish I would have thought of that.
Thaats why you come to this room!
Factor it like you would factor a quadratic, even though it's not a quadratic.
It IS a quadratic!
2 cos^2(x) - 1 = cos x 2 cos^2(x) - cos x - 1 = 0 (2 cos x + 1)(cos x -1) = 0 cos x = - 1/2 and cos x = 1
I assume you wanted to solve for cos x, and not angles for x, as you haven't given interval for angles, etc.
Sorry, a quadratic is a second degree expression of in one variable. In this case cos x is not a variable, but a function. Again, it can be factored like a quadratic, but it is not one.
It is a quadratic equation.
Makes no difference if it is x, y, cos x, or whatever you want to call it.
Yes, it does make a difference. A quadratic is a second-degree POLYNOMIAL expression. In teaching precalculus, I made your mistake for years until corrected by a visiting professor. 2 cos^2(x) - cos x - 1 is a "quadratic type" expression, but not a quadratic. Is it a fine point? Yes. Is mathematics chock-full of fine points? Yes, again.
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