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OpenStudy (anonymous):
trigo identities. proving!! help me with this.. please
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OpenStudy (anonymous):
wait..
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
rsin theta = r^3cos^3 theta/ 2a - r costheta
OpenStudy (anonymous):
i need to get the real answer which is 2a sin theta tan theta..
OpenStudy (ranga):
The left side may have to be r^2sin^2(theta) if this is derived from your previous problem.
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OpenStudy (anonymous):
yes yes
OpenStudy (anonymous):
now im lost..
OpenStudy (anonymous):
so what are the correct terms? the ones above are wrong?
OpenStudy (anonymous):
r^2sin^2 theta = r^3cos^3 theta/ 2a - r costheta
OpenStudy (ranga):
Multiply throughout by (2a/r).
You will have a quadratic equation. Solve for r.
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OpenStudy (anonymous):
the a and r are throwing me, we never played with that in these equations.
cos^3 = 1-sin^2(theta)cos(theta)
OpenStudy (anonymous):
actually this is a cartesian to polar conversion..
OpenStudy (anonymous):
im backing out lol
OpenStudy (ranga):
Why don't you give the original problem here too.
OpenStudy (anonymous):
what level of math do we see this in?
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OpenStudy (anonymous):
analytic geometry
OpenStudy (anonymous):
y^2 = x^3 / 2a - x
OpenStudy (anonymous):
I didnt see it in trig, ahh I haven't taken that.
OpenStudy (anonymous):
and i need to derive r= 2a sin theta tan theta
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