trigo identities. proving!! help me with this.. please
wait..
:)
rsin theta = r^3cos^3 theta/ 2a - r costheta
i need to get the real answer which is 2a sin theta tan theta..
The left side may have to be r^2sin^2(theta) if this is derived from your previous problem.
yes yes
now im lost..
so what are the correct terms? the ones above are wrong?
r^2sin^2 theta = r^3cos^3 theta/ 2a - r costheta
Multiply throughout by (2a/r). You will have a quadratic equation. Solve for r.
the a and r are throwing me, we never played with that in these equations. cos^3 = 1-sin^2(theta)cos(theta)
actually this is a cartesian to polar conversion..
im backing out lol
Why don't you give the original problem here too.
what level of math do we see this in?
analytic geometry
y^2 = x^3 / 2a - x
I didnt see it in trig, ahh I haven't taken that.
and i need to derive r= 2a sin theta tan theta
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