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Mathematics 15 Online
OpenStudy (anonymous):

Write cos x in terms of cot x

OpenStudy (raden):

first, use this identity csc^2 (x) = (cot^2 x + 1) and we knowed that csc = 1/sin so, the identity above can be written as 1/sin^2 (x) = (cot^2 x + 1) or sin^2 (x) = 1/(cot^2 x + 1) then use the identity : sin^2 (x) = 1 - cos^2 (x) now, we get sin^2 (x) = 1/(cot^2 x + 1) 1 - cos^2 x = 1/(cot^2 x + 1) or cos^2 x = 1 - 1/(cot^2 x + 1) (simplied again) cos^2 x = (cot^2 x + 1 - 1)/(cot^2 x + 1) cos^2 x = (cot^2 x)/(cot^2 x + 1) and finally, we get cos(x) = sqrt[(cot^2 x)/(cot^2 x + 1)]

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