Question

cartesian to polar conversion..

Answer 1

y^2 = x(x-a)^2/ 2a- x..

the answer is r^2 - 2arsec theta + a^2 = 0..

Answer 2

need a step by step process

Answer 3

An equation can't be converted into polar coordinates. What can you do about that?

Answer 4

it can be..

Answer 5

Okay, so what do you have to do first?

Answer 6

cartesian to polar..

Answer 7

ok, wait..

Answer 8

Yes, but what is the first step therein?

Answer 9

substituting..

Answer 10

$$x = r\cos \theta \\ y = r\sin \theta$$
Do it.

Answer 11

\[r^2 \sin^2 \theta= \frac{ rcos \theta (rcos \theta-a)^2 }{ 2a- rcos \theta }\]

Answer 12

@bloopman thats it. im already lost

Answer 13

Simplify the expression.

Answer 14

pls help..

Answer 15

How do you simplify that expression? Expand what you're given and divide.

Answer 16

how do i do this.. no idea