Question

help with derivative

Answer 1

y=sin(cosx)

Answer 2

I am not sure what to do but I think it would be chain rule

Answer 3

chain rule
\[(f\circ g)'=f(g)\times g'\] with
\[f(x)=\sin(x), f'(x)=\cos(x), g'(x)=-\sin(x)\]

Answer 4

so would it be
sin(cosx)*-sinx

Answer 5

no

Answer 6

the first sine should be a cosine

Answer 7

oh damn it is my fault, i wrote the rule down wrong!!

Answer 8

so cos(cosx)*-sin(x)

Answer 9

i forgot a prime
\[\large (f\circ g)'=f'(g)\times g'\] sorry

Answer 10

yes you are right, but neaten it up by pulling the minus sign out front, so you don't have to write "times minus..."