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Mathematics 13 Online
OpenStudy (anonymous):

A painter has 4 unlabeled cans of paint. The colors of the paint are red, green, blue, and white. If the painter chooses one can of paint at random, what is the probability that the can does not contain green paint?

OpenStudy (anonymous):

What's the probability the can does contain green paint?

OpenStudy (anonymous):

3/4

OpenStudy (anonymous):

why is it 3/4 ??

OpenStudy (anonymous):

P(not green) = 1 - P(green)

OpenStudy (anonymous):

because there are 4 cans in total. only one can is green

OpenStudy (anonymous):

so there are 3 that are not green. so 3 not green in a total of 4 cans

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

no problem

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