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second derivative of sin 2a csc a + cos a
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Easy trick for this question: The expression sin 2a csc a can be simplified to (2 sin a cos a)(1/sin a) = 2 cos a I used the double-angle formula from trig that states sin (2a) = 2 sin a cos a and the fact that csc a = 1 /sin a So the original expression that you want to find the second derivative of, is really 2 cos a + cos a = 3 cos a The first derivative of 3 cos a -s -3 sin a. And the derivative of -3 sin a is -3 cos a. So, the second derivative is -3 cos a.
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