Question

Please help. i dont think im doing these two problems correctly.
5-y ≥ 4
1. What is the solution set?
a. [1≥-∞)
b. (1>-∞)
c. (1<∞)
d. (1≤-∞)
2. Which represents the given compound inequality in interval notation?
x > 8 or x ≤ 4
a. x E (-∞, 4) U [8,∞ )
b. x E (-4, 8]
c. x E [-4,8)
d. x E (-∞, -4] U (8,∞)

Answer 1

what did u do so far?

Answer 2

okay well i subtracted 5 from the left and did the same on the right, then i got
y is greater than or equal to -1

Answer 3

notice y is -y, so u also divide -1 to both side to make the y positive and to isolate it so i would be y>=1

Answer 4

but wouldnt u flip the sign after dividing by -1?

Answer 5

be careful, when you divide by a negative quantity, you flip the sign

Answer 6

ohhh okay c:

Answer 7

? whhyd u delete it

Answer 8

so, it'll be x<=1
can you find the correct option now ?

i mistyped it as -1

Answer 9

ohh okay :D n yes

Answer 10

i need help with the second one too

Answer 11

u do the same thing u did to the first equation to find x

Answer 12

so add 4 to -5 and 2?

Answer 13

2nd Q is this :
2. Which represents the given compound inequality in interval notation?
x > 8 or x ≤ 4
a. x E (-∞, 4) U [8,∞ )
b. x E (-4, 8]
c. x E [-4,8)
d. x E (-∞, -4] U (8,∞)
right ?

x>8, means from 8 to infinity excluding 8 and can be written as (8, ∞)
( or ) means excluding,
[ or ] means including
so, x<=4 means including 4 , so (-∞, -4]

Answer 14

no this is a differnt problem
x is greater than 8 so u should have (8, inf)
and x is <= 4 so that equals (-inf, 4)
just combine them with U sign

Answer 15

o wait wrong problem.. nvm that last message

Answer 16

the four should have a closing bracket like @hartnn said since the sign is >=

Answer 17

so its a? :D

Answer 18

Yes

Answer 19

correct :)

Answer 20

thanks so much you guys :)

Answer 21

quick question??

Answer 22

yes ?

Answer 23

i am on a different problem and it says 7 greatter tha x + 5 or x 2 greater than or equal to 3

Answer 24

since it has OR inbetween the two.. would it incluce an putside down U ?

Answer 25

it would be U only,
U = union = OR
upside down U = intersection =AND

Answer 26

so reg U?

Answer 27

7 greatter tha x + 5 or x 2 greater than or equal to 3
= 7>(x+5) U x2>=3