Question

Which illustrates the construction of a perpendicular to a line from a point on the line?

Wait for the graphs

Answer 1

Can you help me ??

Answer 2

Can u help me with this??? @RadEn

Answer 3

I think it is the last one. But to explain my answer it would require a lot of drawings which is too time consuming.

Answer 4

The second one can be eliminated because it uses a point that is not on the line as the problem states. The third one can be eliminated because it uses two points on the line.

Answer 5

its ok its ok, I don't want you to waist your time that's would be dumb, so it can eather be the first or the last

Answer 6

I think it is the last. If you have a ruler and a compass you can try this:

Draw a line. Choose a point on the line. Let us call it A.

Set the compass to some radius and draw an arc so it intersects the line at point B on the left and another arc that intersects the line at point C on the right.

Now increase the radius of the compass a little more and draw an arc from each of the points B and C just like they did it in the diagram and let them intersect at point D. JDraw a line joining A and D and you will see that AD is perpendicular to the original straight line.

Answer 7

Ok ill try that, hold up

Answer 8

ok I did it

Answer 9

AB = AC because we set the compass to the same radius when drawing arcs from A to get B and C.

BD = CD because we used a radius (slightly bigger than before) but the same setting to get point D.

The third side AD is shared by both triangles.

So the two triangles are similar. So their corresponding angles must be the same.

So angle DAB = angle DAC.

But DAB + DAC = 180 degrees.

So each must be 90 degrees.

Therefore DA is perpendicular to BC.

Answer 10

ahh ok , I see :) startin to get it

Answer 11

Alright!

Answer 12

yes thank you, your great , lifesaver :) @ranga

Answer 13

You are welcome!