Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

What is the equation of the following graph?

OpenStudy (anonymous):

Do you have an attachment?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Let me see it

OpenStudy (anonymous):

OpenStudy (anonymous):

A. f(x) = x2 - 2x + 3 B. f(x) = -x2 + 2x - 3 C. f(x) = -x2 - 2x - 3 D. f(x) = x2 + 2x - 3

OpenStudy (anonymous):

I dont know how to get it to a(x-h)^2+k

OpenStudy (anonymous):

its the last one, the -3 will move it down and the + 2x will move it left

OpenStudy (compassionate):

You have a parabola. x = -3 x = 1 Your point is maximum at -4 Use the equation: f(x) = a(x-h)²+k Take an equation say: f(x) = x2 - 2x + 3 2(x^2 - 2x) + 3 <-- Now we need to solve that. I have work to do, but I hope this helped somewhat.

OpenStudy (anonymous):

ohh ok i get it

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!