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Mathematics 13 Online
OpenStudy (anonymous):

Vectors, Help

OpenStudy (anonymous):

OpenStudy (anonymous):

I don't know if i should take one from another or use the sqrt(x2-x1)^2 + (y2-y1)^2, etc

OpenStudy (anonymous):

Where are you stuck?

OpenStudy (anonymous):

Just use subtraction. You're trying to find a vector, not a scalar.

OpenStudy (anonymous):

Finding the displacement vector

OpenStudy (anonymous):

Okay, so i don't need to use the long formula similar to distance formula

OpenStudy (anonymous):

You are trying to find the magnitude, which is a scalar, but it isn't asking for that.

OpenStudy (anonymous):

And for the angle do i do

OpenStudy (anonymous):

\[ \mathbf a\cdot \mathbf b=\|\mathbf a\|\|\mathbf b\|\cos\theta \]

OpenStudy (anonymous):

\[\cos ^{-1}(x 1x2+y1y2+z1z2/|P1P2||P1P3|) \]

OpenStudy (anonymous):

Basically what I wrote is what you put when solving for \(\theta\)

OpenStudy (anonymous):

Try to understand vectors, not just memorize formula.

OpenStudy (anonymous):

ok

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