Question

Hi. I was wondering if someone could help me solve this physics problem? A projectile is fired from the top of a 200.0m cliff above a valley. It's initial velocity is 70m/s at an angle if elevation of 60 degrees. Neglect air resistance determine the final velocity of the projectile and the max height above the ground. I found the max height which is 387m, but I can't seem to find the final velocity. :(

Answer 1

ok, so for the final velocity we will look at two moments of the projectile's path. the first is the time when the projectile is at it's peak, and the other is when it is hitting the ground.
ok?

Answer 2

so, the max height you got of 387m, is that 387m above the top of a 200m cliff, or above the ground?

Answer 3

@My15girl

Answer 4

above the ground.

Answer 5

great!
ok, then all you need is this equaition...

V^2 = V^2 + 2a(s2-s1)
the left V is the final velocity (meters/second)
the right V is initial velocity (meters/second)
the a is for acceleration (meters / second^2)
the s2 is for the final posistion of the projectile (meters)
the s1 is for the initial posistion of the projectile (meters)

can you make sense which numbers will go where?

Answer 6

yeah I can