which is the equations for the line perpendicular to y=5/3x+11 1/3 and containing p(-2,3)
y-2=-3/5(x-3)
y=-5/3x+4 1/3
y=-3/5x+4 1/5
y=3/5x+4 1/5

Question

which is the equations for the line perpendicular to y=5/3x+11 1/3 and containing p(-2,3)
y-2=-3/5(x-3)
y=-5/3x+4 1/3
y=-3/5x+4 1/5
y=3/5x+4 1/5

anonymous · Answer

basic information
perpendicular lines have slopes that are negative inverses of each other
if one has the slope and a point of that slope:point-slop form can be used to find the line's equation

anonymous · Answer

point-slope form:y-y1=m(x-x1)

anonymous · Answer

so the last one?

anonymous · Answer

well the slope would be -3/5

anonymous · Answer

it is not B, or D

anonymous · Answer

but they already have a -5/3 in the first part of the question

anonymous · Answer

?
y=5/3x+11 1/3 <---did you make a typo?

anonymous · Answer

oh yes my bad. its supposed to be y=-5/3x+11 1/3

anonymous · Answer

ok then the slope would be 3/5 so yes D

anonymous · Answer

yay thank you!