I need to find the gradient of the normal to the line segment AB where A is (-1,5) and B is (3,4). AB is a straight line. Help please?!

Question

I need to find the gradient of the normal to the line segment AB where A is (-1,5)  and B is (3,4). AB is a straight line. Help please?!

anonymous · Answer

Gradient of normal line is just the slope of the line perpendicular to AB. Find the slope of AB, and the gradient of the normal line will be the negative reciprocal of whatever the slope of line AB is.

anonymous · Answer

Thank you! i think I've got it now

anonymous · Answer

whats your answer?

anonymous · Answer

i got the gradient to be -0.25 for AB

anonymous · Answer

Slope of AB = -1/4

Gradient of normal line is the negative reciprocal of -1/4, which is 4.

anonymous · Answer

You are correct for slope of AB = -1/4 or -0.25

anonymous · Answer

brilliant, thank you

anonymous · Answer

Welcome.