Question

How do you write y=x^2-2x-3 in Vertex & Intercept form? y-5=-2(x+1)^2 in Standard & Intercept form? y=(x=2)(x-3) in Standard and Vertex form?

Answer 1

Using Quadratic Formula

Answer 2

the so-called intercept or x-intercepts to be exact form, is also the roots or solutions for the quadratic, you get them by setting y = 0 and factoring the equation into binomials usually

the vertex form you'd get it by "completing the square", thus making the "x" components into a perfect square trinomial

Answer 3

so what would the formulas be so i know how to plug those equations into the different forms?

Answer 4

hmmm are you just looking for the vertex of it?

Answer 5

there is no formula per se on that, to get the solutions, there is one, no always needed though

Answer 6

i dont need the solutions, i just need to be able to write them in different forms. i'll attach the question so you can see it

Answer 7

ok... do you know what a perfect square trinomial is?

Answer 8

i dont think so

Answer 9

http://www.youtube.com/watch?v=xGOQYTo9AKY <--- that shows how to get the vertex form

Answer 10

the intercept form is the factored form, from where you'd get the solutions http://www.youtube.com/watch?v=SDe-1lGeS0U

Answer 11

thank you so much! :)

Answer 12

yw