Please Help! How can a shape look the same after being rotated?
won't it look the same if its rotated 360 degrees?
Yes
where my medal at then?
circle
I have 2 more questions, can you answer them?
shoot.
If its symmetric about its x/y axis, then a 180 degree rotation is guaranteed.
4. How does the distance from one point of the pre-image to the reflection line relate to the reflected image point? Is this relationship true for all reflections? How do you know?
symmetric shapes such as square,
A vector is a mathematical object that has direction and magnitude. What is another way you can describe and define a translation?
Translation: moving all the points in the object by a vector A... I guess?
Ok
In component form, vectors are give x and y distances. Adding these distances too all points being transformed will retain its shape and hence be a true transform.
Can you answer number 2?
4. The distance from one point of the pre-image to the reflection line is 1/2 of distance from that point to reflected image point. This relationship holds for all reflections every point A and point on image A' are equidistant to the reflection line.
I mean 4
2 seems to be by defintion. By definition, all points on one side of the reflection line are equal distant from its imaged point. So the distance from 1 point to another is 2x where x is the distance to the line.
Thanks!
@kmeis002 how do you know #2? Last question
Well, think of a 180 degree rotation. (images to follow). You can say a 180 degree rotation is a flip across the x axis and a flip across the y. If they are symmetric about both, it must be the same after both flips and therefore after a rotation of 180
Huh?
Sorry I was looking at 1. One moment
Ok
A vector is an object which has a X distance and Y distance, sometimes labelled \[ v = <v_x , v_y> \] Basically, if you move a point, or series of points along the vx and the vy, there will be know rotation and it will be purely rotational. So you can describe a translation simply by adding a vector to your initial points since its magnitude is a distance. This means you have simply moved each point a distance the same direction.
Lol I meant this one, just tell me how do you know. How does the distance from one point of the pre-image to the reflection line relate to the reflected image point? Is this relationship true for all reflections? How do you know?
Wait I lied, can you answer the entire question for me? If not that's fine
Sure, by defintion, the reflection line is the line where all points on one side (pre-image) are equal distance from the the reflection line as the other side (image points). This means if point A has a distance of 2 from the image like, the its image point A' must also have a distance of to, so the distance between A and A' is 2+2 = 4. This works for any distance. So if A is x away from the mirror line, then A' is x away and therefore the distance between the two AA' is x+x = 2x.
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