26+6b ≥ 2(3b+4) i've been out of school for a year and i'm extremely rusty i apologize
Are you trying to find b?
it just says to solve it and graph it. if i could solve it, i'll have no trouble graphing it. that part i remember
Ok so just think the inequality symbol as a = sign so then just solve for b.
i got b=22..... i don't think that's right
if you expand the right-hand side, what do you get?
what
if you were to expand say 2(3b+4), what would that expand to?
oh, 6b+12
hmmm there's no solution, as far as I can tell..... because anyhow 2 * 4 = 8 \(\ne 12\)
\(\bf 26+6b\ge 2(3b+4) \implies 26\cancel{+6b}\ge \cancel{6b}+8\implies 26 \ge 8\)
26 + 6b >= 2(3b + 4) 26 + 6b >= 6b + 8 6b - 6b >= 8 - 26 0 >= - 18 (incorrect) I agree.....no solution
hmmm.... actually 0 is greater than -18 I was wondering on that. because 26 is indeed greater than 8, I mean, is a valid inequality
on the negative side, the closer to 0, the greater than number
perfect, that's one of the choices. thank you guys so much
oops,,,my bad...I should have caught that 0 is greater then -18. So what is the answer ? 0b >= -18
well. is valid... now.... how to graph it.... hmmm maybe just 2 dots =) one at 26 and one at 8 hehhe
oh, well the answer was all real numbers i failed
well...yes because any number times 0 will equal 0, and that would be less then -18.
oops...greater
I'M SO BAD AT THIS WOW thank you guys
you will get better...it just takes practice. And believe me when I tell you if I had a dollar for every mistake I made, I would be rich.
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