Back to the basics: I know the sqrt of 343 is 7sqrt(7). What I'd like to learn is how we got there. Is there any easy way of finding out 7x7x7=343?
\[\sqrt{343}=\sqrt{49*7}=\sqrt{49}*\sqrt{7}=7\sqrt{7}\]
assuming you don't have a calculator, you might want to memorize some of these divisibility rules https://en.wikipedia.org/wiki/Divisibility_rule#Divisibility_rules_for_numbers_1.E2.80.9320 It is also helpful to memorize the first few prime numbers https://en.wikipedia.org/wiki/List_of_prime_numbers#The_first_500_prime_numbers but 343 is not a particular easy number to factor.
if you know the divisibility rule for 7: for 343, do 34 - 2*3= 34-6=28 28 is divisible by 7. once you find 7*49= 343 you should know 47= 7*7
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