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Can anyone help me with finding the equation of a line with the points (-3,-4) and (1,-2)?
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first find the slope
y2-y1/x2-x1 ---> slope formula
first you need to find the slope
(-2-(-4))/1-(-3) =2/4 = 1/2 is the slope
now use this formula to find the equation of a line y-y1 = m(x-x1) m represents the slope now just plug the point in to the equation
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which would be y-(-4) =(1/2)(x-(-3)) y+4 =(1/2)(x+3) y = 1/2x + 3/2 + 4 y = (1/2)x + 11/2
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