A volume of 50.0 mL of 0.400 M HBr at 24.35°C is added to 50.0 mL of 0.400 M NaOH, also at 24.35°C. The final temperature is 27.06°C. Calculate the enthalpy change, H, in kJ for the following reaction:
HBr(aq) + NaOH(aq) NaBr(aq) + H2O(l)
(Heat capacity of the system is 0.418 kJ/°C.)

−28.4 kJ
−56.7 kJ
−324 kJ
−113 kJ

Question

A volume of 50.0 mL of 0.400 M HBr at 24.35°C is added to 50.0 mL of 0.400 M NaOH, also at 24.35°C. The final temperature is 27.06°C. Calculate the enthalpy change, H, in kJ for the following reaction: 
HBr(aq) + NaOH(aq)  NaBr(aq) + H2O(l)
(Heat capacity of the system is 0.418 kJ/°C.)

 	
  	−28.4 kJ
  	−56.7 kJ
  	−324 kJ
  	−113 kJ

anonymous · Answer

Can someone show me how to solve this in steps?