Δ DOG has coordinates D (3, 2), O (2, -4) and G (-1, -1). A translation maps point D to D' (2, 4). Find the coordinates of O' and G' under this translation.
Select one: a. O' (-1, 1);G' (1, -2) b. O' (3, 0);G' (-1, -1) c. O' (0, -3);G' (-3, 0) d. O' (1, -2);G' (-2, 1)
@Directrix can you help me please
Well, I'm not good on these but I'll hit it (or something) with my best shot. D(3,2) and D' is (2,4). So, the translation took 3 to 2 and then 2 to 4. So, I'm thinking the translation is (x,y) --> (x - 1, y + 2)
@Edge can you help me please
im back srry bout that
What did you get for O'
So, take point O, O (2, -4), and subtract 1 from its x-coordinate and then add two to its y-coordinate and post what you get.
ummm...
2 - 1 = ? -4 + 2 = ?
I had to go do something so im lost
Just answer this: 2 - 1 = ? -4 + 2 = ? @Edge
am I supposed to fing coordintes or something
I asked you to do these calculations. If you do not want to do them, let me know. 2 - 1 = ? --> Two minus one = ? -4 + 2 = ? --> Negative four plus two = ?
ok 2-1=1 obviously and -4+2=-6
no its not -6 its -2
Okay, so O (2, -4) is sent to O' (1, -2).
yes.. im starting to get it
Look in the options and find the one that looks like O'(1, -2).
it would be D right
Yes. I'm thinking we need to check G to G'
uhmmm ok then
G (-1, -1) to G' (x,y) --> (x - 1, y + 2) What is -1 - 1 = ? What is -1 + 2 = ?
@Edge
-2 and 1
Yay so it really is D
G (-1, -1) --> G' (-2, 1) Correct.
yes ur the best help ever
Thanks.
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