Question

Simplify: (4x)2(-2y3)

-8x2y3
None of the above
-32x2y3
-8xy6
2. Simplify: (3x+2y)(3x-2y)=

9x2+12xy+4y2
None of the above
9x2+4y2
9x2-4y2

Answer 1

\((4x)^2(-2y^3) \)

What does squaring a quantity mean?

Answer 2

1=none of the above
what is 2

Answer 3

1 is incorrect

Answer 4

then what would it be

Answer 5

Would you like to answer my question above?
We'll go over the problem step by step.

Answer 6

The left side of the first problem is squaring the quantity 4x.
What does squaring a quantity mean?

Answer 7

Here's a simpler question.
What do you do to calculate \(5^2\) ?

Answer 8

25

Answer 9

You gave me the answer, and the answer is correct, but I asked what do you do to find the answer?
You multiply 5 by 5, right?

Answer 10

ya man

Answer 11

In your first problem, you need to square 4x.
What do you do to square 4x?
You must multiply 4x by 4x.
What is 4x * 4x?

Answer 12

16

Answer 13

The 4 times the 4 equals 16. That's good, but you also have x times x.
\((4x)^2 = 4x \times 4x = 16x^2 \)

Answer 14

The entire problem is:

\((4x)^2(-2y3) \)

\(= 16x^2(-2y^3) \)

\(=-32x^2y^3\)

Notice that one of the choices above is the answer.

Answer 15

how bout this problem
Simplify: 9x^3+6x^2+3x/3x
None of the above
3x2+2x+1
3x2-2xy-2
3x4+6x3+x2

Answer 16

Wait, didn't you want to do the second problem above also?

Answer 17

2. Simplify: (3x+2y)(3x-2y)=

9x2+12xy+4y2
None of the above
9x2+4y2
9x2-4y2

Answer 18

This is a famous multiplication in math.
When you multiply a sum and a difference of the sdame two quantities.
The general pattern is:
\( (a + b)(a - b) = a^2 - b^2\)

Notice that the two things you are adding, a and b, you are also subtracting, a - b.
You are multiplying a sum and a subtraction (difference) off the same two things.
All you need to do is square both of the things and subtract them. a^2 - b^2.

Answer 19

Look at your problem:

(3x+2y)(3x-2y)=

You are adding 3x and 2y, and you are subtracting 3x - 2y.
To multiply them together, square the two things, (3x)^2 and (2y)^2 and subtract them.

\( (3x + 2y)(3x - 2y) = \)

\(= (3x)^2 - (2y)^2 \)

\(= 9x^2 - 4y^2 \)

This is one of your choices up there.

Answer 20

Simplify: \( \dfrac{9x^3+6x^2+3x}{3x} \)

Divide every term in the numerator by the denominator.

\( \dfrac{9x^3+6x^2+3x}{3x} \)

\( = \dfrac{9x^3}{3x} + \dfrac{6x^2}{3x} + \dfrac{3x}{3x} \)

\(= 3x^2 + 2x + 1\)

Answer 21

Simplify: (7x-2)+(2x+17)=

9x+19
9x2+19
9x+15
9x2+15