Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

How do I find the intercepts, vertex, and axis of symmetry for the attached graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

the vertex is the point in the midle, and axis of symetry is cut down in the middle if the figure.

OpenStudy (anonymous):

This is a wonderful question! To find the Intercept: For X intercept, you can look at where your parabola crosses the x - axis (horizontal) (its not uncommon to have 1, 2, or 0) For Y Intercept, you can look at where your parabola crosses the y - axis (vertical) The vertex is the point of your parabola, and the axis of symmetry is the same x of your vertex. ------------------------------------------------------------------ Instructions for finding Intercepts, Vertex, Axis of symmetry WITHOUT a graph Axis of symmetry = X = (-b/2a) Plug that number into you function to get the other half of your vertex. To find the intercepts, plug in 0 for x in the y intercept Plug in 0 for y in the x intercept Hope that helps!

OpenStudy (dan815):

|dw:1381954635498:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!