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Two pieces, if we can believe the answer choices. Ignoring the absolute values: x + 3 > 7 leads to x > 4 Whoops! I guess that's all we need, since there is only one of those int he answer set. Let's do the other one, anyway. NOT ignoring the absolute values: x + 3 < -7 leads to x < 10 Okay, now we're REALLY done.
\(\bf |x + 3| > 7\implies \begin{cases} +(x + 3) > 7\\ \quad \\ \bf -(x + 3) > 7 \end{cases}\) solve each scenario, you'd get 2 values for "x"
Don't ask that. Please look at the results and compare them to the answer choices.
What if I write it correctly and use x < -10, instead of what I wrote above?
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