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1-4d is greater than or equal to 4-d Solve for d.
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\[\large 1 - 4d \ge 4 -d\] you want to get d alone. Start by adding d to both sides (that'll get rid of -d on the left)
\[1-5d \ge 4-2d\] ?
-d+d is zero -4d + d is -3d
I'm confused.
-1+1 is zero... -4 + 1 is -3 same thing applies to -d+d and -4d + d
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So what does the equation look like now?
add d to both sides, and simplify this \[\large 1 - 4d +d \ge 4 -d + d\]
So...what do I do now?
simplify it :P like i showed above... the -d+d is zero. -4d+d is -3d. So simplify the above
so the -d+d cancels off...what about the -4d+d?\[\large 1 - 4d +d \ge 4 \]
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1−4d+d≥4 1-4d+d-4≥_ ?
simplify the left, leave the 4 alone for now 1−3d≥4
now subtract 1 on both sides
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