Question

HELP PLEASE: Is the solution to Amplitude (1/2), period 6pi, horizontal shift two units to the right

1/2 sin 3.28t +2 ?

Answer 1

hmm what's the 3.28? and did you mean \(\bf \cfrac{1}{2}sin(3.28t)+2\quad ?\)

Answer 2

yes

Answer 3

3.28 is for the 2pi/6pi which is my desired amount

Answer 4

\(A\times sin(\cfrac{2\pi}{T}-\phi)\), where \(A\) is amplitude, \(T\) is period and \(\phi \) is phase shift.

You have \(A=\cfrac{1}{2}\), \(T=6\pi\) and \(\phi=2\).

Note: \(\cfrac{2\pi}{6\pi}=\cfrac{1}{3}\) for your frequency.

Answer 5

so the equation would be 1/2 sin(1/3) +2 ?

Answer 6

Almost, I forgot the \(t\):
$$
\cfrac{1}{2}\times sin(\cfrac{t}{3}-2)
$$
Don't forget to include the 2 inside the parenthesis, which shifts the entire sine function to the right by 2 time units.

Answer 7

thank you

Answer 8

you're welcome