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Chemistry 14 Online
OpenStudy (toxicsugar22):

Calculate the mass of water produced when 3.21g of butane reacts with excess oxygen.

OpenStudy (dan815):

okay write the reaction down

OpenStudy (toxicsugar22):

2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g)

OpenStudy (toxicsugar22):

is that it

OpenStudy (dan815):

ok so

OpenStudy (dan815):

3.21 grams = how many moles of butane

OpenStudy (dan815):

2 moles of butane will result in 10 moles of h20

OpenStudy (dan815):

so x number of moles of butane will result in 5*x number of moles of h20 then u calculate the masss of the h20

OpenStudy (toxicsugar22):

18.02 is h20 mass

OpenStudy (toxicsugar22):

right

OpenStudy (dan815):

yeah

OpenStudy (toxicsugar22):

so 18.02 is answer

OpenStudy (dan815):

what the 0,0

OpenStudy (dan815):

18.02 is 1 molar mass

OpenStudy (dan815):

okay let me explain how these things are done

OpenStudy (dan815):

basically the masses you see on the period table

OpenStudy (dan815):

are given to you per mole a mole of an element = 6.022*10^(22?) # of atoms of that element or something like that

OpenStudy (dan815):

someone decdided to take like a billinmillion million molecules of some element and decided to weight them, and record the mass and put it on the period table

OpenStudy (dan815):

so that became a mole!

OpenStudy (toxicsugar22):

ok

OpenStudy (dan815):

oka now you have a mole of a compound

OpenStudy (dan815):

you can find the 1 molar mass of a compound.. but u only have 3.21 grams of that compound, how many moles is that?

OpenStudy (dan815):

what is the molar mass of butane

OpenStudy (toxicsugar22):

so 18.02 is answer

OpenStudy (dan815):

=O

OpenStudy (dan815):

i will beat u with a stick

OpenStudy (dan815):

can u tell me why u are so confused

OpenStudy (dan815):

wut .. the just stop!

OpenStudy (dan815):

just stop go back to basics.. why are u confused

OpenStudy (dan815):

stop fiddling around with random numbers and understand what is going on

OpenStudy (toxicsugar22):

can you tell me and give me the solution please as it is hard to communicate via eami and that is the way i will understand

OpenStudy (dan815):

i told you already

OpenStudy (dan815):

3.21 grams = how many moles of butane? 2 moles of butane will result in 10 moles of h20 so x number of moles of butane will result in 5*x number of moles of h20 then u calculate the masss of the h20

OpenStudy (toxicsugar22):

ok

OpenStudy (toxicsugar22):

this is my very first time doing it alone so I am not that comfortable with these problems

OpenStudy (dan815):

then u need to do more of these problems

OpenStudy (toxicsugar22):

can you provide me a solution and anser so I can take notes without interputing

OpenStudy (toxicsugar22):

i will do more

OpenStudy (toxicsugar22):

i promise

OpenStudy (dan815):

you know I have an exam tomorrow

OpenStudy (toxicsugar22):

ohh sorry

OpenStudy (dan815):

u arent even doing some of the stesps i gave u

OpenStudy (dan815):

first tell me the molar mass of butane

OpenStudy (toxicsugar22):

yes 18.02 is mass of h20

OpenStudy (toxicsugar22):

butane mass is 58.122

OpenStudy (dan815):

ok

OpenStudy (dan815):

if 58.122 grams = 1 mol 3.21 grans = how many mols?

OpenStudy (toxicsugar22):

18.106

OpenStudy (dan815):

-.-

OpenStudy (dan815):

take a deep breath okay

OpenStudy (dan815):

just relax lets calmly think about this

OpenStudy (toxicsugar22):

i divided the mass of butane by 3.21

OpenStudy (dan815):

58.122 grams = 1 mol 3.21 grams = ___ mols

OpenStudy (dan815):

right now 1 molar mass of buta weights 58.122 grams

OpenStudy (dan815):

but we only have 3.21 grams, 3.21 grams is a lot smaller than 58.122 grams

OpenStudy (dan815):

how many times 3.21 smaller than 58.122

OpenStudy (toxicsugar22):

by 18 times

OpenStudy (dan815):

okay so

OpenStudy (dan815):

the number of moles will be 18 times smalller too right

OpenStudy (dan815):

i mean how many moles* would you have for 3.21 grams

OpenStudy (toxicsugar22):

1.87* 10^23

OpenStudy (dan815):

T_T you are killing me here

OpenStudy (dan815):

how many mols

OpenStudy (toxicsugar22):

1 mole = 6.02*10^23

OpenStudy (toxicsugar22):

so do we divide this by 3.21

OpenStudy (dan815):

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