Calculate the mass of water produced when 3.21g of butane reacts with excess oxygen.
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OpenStudy (dan815):
okay write the reaction down
OpenStudy (toxicsugar22):
2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g)
OpenStudy (toxicsugar22):
is that it
OpenStudy (dan815):
ok so
OpenStudy (dan815):
3.21 grams = how many moles of butane
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OpenStudy (dan815):
2 moles of butane will result in 10 moles of h20
OpenStudy (dan815):
so x number of moles of butane will result in 5*x number of moles of h20 then u calculate the masss of the h20
OpenStudy (toxicsugar22):
18.02 is h20 mass
OpenStudy (toxicsugar22):
right
OpenStudy (dan815):
yeah
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OpenStudy (toxicsugar22):
so 18.02 is answer
OpenStudy (dan815):
what the 0,0
OpenStudy (dan815):
18.02 is 1 molar mass
OpenStudy (dan815):
okay let me explain how these things are done
OpenStudy (dan815):
basically the masses you see on the period table
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OpenStudy (dan815):
are given to you per mole
a mole of an element = 6.022*10^(22?) # of atoms of that element or something like that
OpenStudy (dan815):
someone decdided to take like a billinmillion million molecules of some element and decided to weight them, and record the mass and put it on the period table
OpenStudy (dan815):
so that became a mole!
OpenStudy (toxicsugar22):
ok
OpenStudy (dan815):
oka now you have a mole of a compound
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OpenStudy (dan815):
you can find the 1 molar mass of a compound..
but u only have 3.21 grams of that compound, how many moles is that?
OpenStudy (dan815):
what is the molar mass of butane
OpenStudy (toxicsugar22):
so 18.02 is answer
OpenStudy (dan815):
=O
OpenStudy (dan815):
i will beat u with a stick
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OpenStudy (dan815):
can u tell me why u are so confused
OpenStudy (dan815):
wut .. the just stop!
OpenStudy (dan815):
just stop go back to basics.. why are u confused
OpenStudy (dan815):
stop fiddling around with random numbers and understand what is going on
OpenStudy (toxicsugar22):
can you tell me and give me the solution please as it is hard to communicate via eami
and that is the way i will understand
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OpenStudy (dan815):
i told you already
OpenStudy (dan815):
3.21 grams = how many moles of butane?
2 moles of butane will result in 10 moles of h20
so x number of moles of butane will result in 5*x number of moles of h20 then u calculate the masss of the h20
OpenStudy (toxicsugar22):
ok
OpenStudy (toxicsugar22):
this is my very first time doing it alone so I am not that comfortable with these problems
OpenStudy (dan815):
then u need to do more of these problems
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OpenStudy (toxicsugar22):
can you provide me a solution and anser so I can take notes without interputing
OpenStudy (toxicsugar22):
i will do more
OpenStudy (toxicsugar22):
i promise
OpenStudy (dan815):
you know I have an exam tomorrow
OpenStudy (toxicsugar22):
ohh sorry
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OpenStudy (dan815):
u arent even doing some of the stesps i gave u
OpenStudy (dan815):
first tell me the molar mass of butane
OpenStudy (toxicsugar22):
yes 18.02 is mass of h20
OpenStudy (toxicsugar22):
butane mass is 58.122
OpenStudy (dan815):
ok
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OpenStudy (dan815):
if 58.122 grams = 1 mol
3.21 grans = how many mols?
OpenStudy (toxicsugar22):
18.106
OpenStudy (dan815):
-.-
OpenStudy (dan815):
take a deep breath okay
OpenStudy (dan815):
just relax lets calmly think about this
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OpenStudy (toxicsugar22):
i divided the mass of butane by 3.21
OpenStudy (dan815):
58.122 grams = 1 mol
3.21 grams = ___ mols
OpenStudy (dan815):
right now 1 molar mass of buta weights 58.122 grams
OpenStudy (dan815):
but we only have 3.21 grams, 3.21 grams is a lot smaller than 58.122 grams
OpenStudy (dan815):
how many times 3.21 smaller than 58.122
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OpenStudy (toxicsugar22):
by 18 times
OpenStudy (dan815):
okay so
OpenStudy (dan815):
the number of moles will be 18 times smalller too right
OpenStudy (dan815):
i mean how many moles* would you have for 3.21 grams
OpenStudy (toxicsugar22):
1.87* 10^23
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