Question

Write an equation of the line with slope of -4/3 that passes thru the point (-6,2)?

Answer 1

Do you know about y=mx+b?

Answer 2

Where:
M = Slope
B = Y-intercept

Answer 3

Yeah

Answer 4

Plug-in the values

Answer 5

Great just plug in the values.
Slope: -4/3
x,y: (-6,2)
So: \(y=mx+b\)
\[2=\frac{-4}{3}(-6)+b\]

Answer 6

Can you solve for b or do you need my help? Do not be afraid to ask :-).

Answer 7

Actually yeah if you wouldnt mind

Answer 8

Okay then.
\[2=\frac{-4}{3}(-6)+b\]
We need to solve for \(b\).
So:
\[2=\frac{-4}{3}(-6)+b\]
Becomes:
\[2=8+b\]
Reverse the equality in \(2 = b+8\) in order to isolate b to the left hand side.
\(2 = b+8\) is equivalent to \(b+8 = 2\):
\(b+8 = 2\)
Isolate terms with b to the left hand side.
Subtract 8 from both sides:
\(b+(8-8) = 2-8\)
Look for two terms that sum to zero.
\(8-8 = 0\)
\(b = 2-8\)
Evaluate \(2-8.\)
\(2-8 = -6\)
Answer:
\(b = -6\)