Question

I need to factor this problem, 6x^2+60x+54

Answer 1

\[6x ^{2}+60x+54\]

Answer 2

oki here we go...

take 6 as common factor what do you get?

Answer 3

you would get 6(?)+6x+9

Answer 4

Wait
i think i did it wrong haha

Answer 5

divide by 6, set equal to zero. then think of a number you must add two both side of the equation to complete the square

Answer 6

6(x^2+6x+9)

Answer 7

is that it?

Answer 8

60/6 do long division if you have to

Answer 9

6(x^2+10x+9)

Answer 10

i think thats better right?

Answer 11

or, think of the 'factors' and write them out, and cancel them so (5*2*3*2)/(3*2)

Answer 12

yes it is..! now .. expand it as 6(x^2+9x+x+9)

now can you take something common in 6(x^2+9x+x+9)

Answer 13

so like, i have 6(x+6x+x+9)

Answer 14

I was abesent one day and im just so confused with factoring for some reason.

Answer 15

okay .. we have to expand it in such way that

product of middle terms would be equal to product of first and last terms...

so we expand x^2+10x+9 as x^2+9x+x+9

now check product of middle terms=9x^2 and product of first and last terms is 9x^2

so our expansion is correct got it?? :)

Answer 16

But where does the a in x^2+9x+(x)+9 come from? the one in ( )

Answer 17

But where does the x* not a in x^2+9x+(x)+9 come from? the one in ( )

Answer 18

because 10x=9x+x

Answer 19

\[6 x^2+60 x+54=6 (x+1) (x+9) \]