Mathematics
8 Online
OpenStudy (anonymous):
If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(4)] 2.
81
257
289
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OpenStudy (anonymous):
x^2 and the 2 at the end being the same.
OpenStudy (anonymous):
so is it f(x)=x^2+1 and g(x)=3x+1, find [f(4)]^2
OpenStudy (anonymous):
yes
OpenStudy (ranga):
Can you tell me what is f(4) when f(x) = x^2 + 1?
OpenStudy (anonymous):
no? I don't know how to do this.
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OpenStudy (anonymous):
take 4 and plug it in the place of x
OpenStudy (ranga):
Just put x = 4 in f(x) and find the value
OpenStudy (anonymous):
this is funtions
OpenStudy (ranga):
f(x) = x^2 + 1
f(4) = 4^2 + 1 = ?
OpenStudy (anonymous):
i don't know..
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OpenStudy (anonymous):
If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(4)] 2.
81
257
289
Those are my three options.
OpenStudy (ranga):
Looks like you just want the answer. I am sorry.
OpenStudy (anonymous):
I'm on my last attempt of this whole lesson and I am stuck on just this question
OpenStudy (anonymous):
what is 4^2?
OpenStudy (anonymous):
4^2 means 4 squared.
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OpenStudy (anonymous):
yea, what does 4 squared equal?
OpenStudy (anonymous):
16?
OpenStudy (anonymous):
yes, so
f(4)= 4^2+1
f(4)=16+1 =?
OpenStudy (anonymous):
that doesn't equal any of my options though.
OpenStudy (anonymous):
remember you have to square f(4)
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OpenStudy (anonymous):
so 33?
OpenStudy (anonymous):
no, what did you get for f(4)=16+1
OpenStudy (anonymous):
33?
OpenStudy (anonymous):
16+1=?
OpenStudy (anonymous):
is 17
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OpenStudy (anonymous):
yes so f(4)=17
so take 17 and square it
(17)^2=?
OpenStudy (anonymous):
289
OpenStudy (anonymous):
and is that one of your options
OpenStudy (anonymous):
If f(x) = x 2 + 1 and g(x) = 3x + 1, find 2f(1) + 3g(4) help me with this question now?
OpenStudy (anonymous):
sure
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OpenStudy (anonymous):
x2 meaning x^2
OpenStudy (anonymous):
for f(1), you would take 1 and plug it in the place of x for the function
f(x) = x^2 + 1
OpenStudy (anonymous):
show me how to plug it in
OpenStudy (anonymous):
so f(1)=1^2+1?
OpenStudy (anonymous):
yup
now what does f(1)=1^2+1=?
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OpenStudy (anonymous):
3
OpenStudy (anonymous):
no, what is does 1^2=?
OpenStudy (anonymous):
1?
OpenStudy (anonymous):
yea, so f(1)=1^2+1=?
OpenStudy (anonymous):
1+1+1 is 3?
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OpenStudy (anonymous):
no, so 1^2= 1 times 1=1
f(1)=1^2+1
f(1)=1+1=?
OpenStudy (anonymous):
4?
OpenStudy (anonymous):
what does 1+1=?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
yea so f(1)=1^2+1=?
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OpenStudy (anonymous):
I'm so confused. is it 5 or 6?
OpenStudy (anonymous):
f(x)=x^2+1
f(1)=1^2+1
f(1)=1+1
f(1)=?
OpenStudy (anonymous):
2?
OpenStudy (anonymous):
1?
OpenStudy (anonymous):
2
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OpenStudy (anonymous):
now what's the next step from 2?
OpenStudy (anonymous):
so since it is 2f(1)
what would 2 times f(1)=?
knowing f(1)=2
OpenStudy (anonymous):
4?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
so thats half of the problem done
2f(1) + 3g(4)
4 + 3g(4)
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OpenStudy (anonymous):
now for g(x)=3x+1
what would you plug in for x, knowing that you are looking for g(4)
OpenStudy (anonymous):
a 4
OpenStudy (anonymous):
yup, what would it look like
OpenStudy (anonymous):
g(4)= 3(4)+1?
OpenStudy (anonymous):
yup, now what does that equal
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OpenStudy (anonymous):
13 + 12?
OpenStudy (anonymous):
no, so 3(4)=?
OpenStudy (anonymous):
12/
OpenStudy (anonymous):
12+1=?
OpenStudy (anonymous):
13
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OpenStudy (anonymous):
so g(4)= 3(4)+1?
OpenStudy (anonymous):
what would it equal
OpenStudy (anonymous):
13 + 14?
OpenStudy (anonymous):
or 13 + 13?
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
g(x)=3x+1
g(4)=3(4)+1
g(4)=12+1
g(4)=?
OpenStudy (anonymous):
g(4)= 13
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
so if you look back it says to find
3g(4)
3 times g(4)=?
knowing that g(4)=13
OpenStudy (anonymous):
13*3 is 39?
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OpenStudy (anonymous):
yup
OpenStudy (anonymous):
now 2f(1) + 3g(4)=?
OpenStudy (anonymous):
4+39?
OpenStudy (anonymous):
43
OpenStudy (anonymous):
yup
WOOOOHOOOOO
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OpenStudy (anonymous):
I hate ALG 2, my teacher doesn't know how to teach
OpenStudy (anonymous):
ohhh that sucks
OpenStudy (anonymous):
you can message me if you have questions
OpenStudy (anonymous):
Thanks.