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OpenStudy (anonymous):
2/y+3 + 3/y-4 = 5/y+6
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OpenStudy (anonymous):
\[\frac{ 2 }{ y+3 } + \frac{ 3 }{ y-4 } = \frac{ 5 }{ y+6 }\]
Are you supposed to solve for y?
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
yah solve for y
OpenStudy (ranga):
Multiply each term by: (y + 3)(y - 4)(y + 6) and simplify
OpenStudy (anonymous):
i did that and got the wrong answer
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OpenStudy (ranga):
Why don't you show the steps here and we will see if we can spot the error.
OpenStudy (anonymous):
too much typing
OpenStudy (ranga):
Multiply each term by: (y + 3)(y - 4)(y + 6)
2(y-4)(y+6) + 3(y+3)(y+6) = 5(y+3)(y-4)
(2y^2 + 4y - 48) + (3y^2 + 27y + 18) = 5y^2 - 5y - 12
5y^2 + 31y - 30 = 5y^2 - 5y - 12
31y + 5y = 30 - 12
36y = 18
y = 1/2
OpenStudy (anonymous):
oh gees thank you so much!
OpenStudy (ranga):
yw
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OpenStudy (anonymous):
but the answer is -11/6
OpenStudy (ranga):
Spotted the mistake.
OpenStudy (ranga):
Multiply each term by: (y + 3)(y - 4)(y + 6)
2(y-4)(y+6) + 3(y+3)(y+6) = 5(y+3)(y-4)
(2y^2 + 4y - 48) + (3y^2 + 27y + 54) = 5y^2 - 5y - 60
5y^2 + 31y + 6 = 5y^2 - 5y - 60
31y + 6 = -5y - 60
36y = -66
y = -66/36 = -11/6
OpenStudy (anonymous):
thank you that helped a lot!!!
OpenStudy (ranga):
I am on east coast time and I should not be up this late. I am quitting for the day.
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OpenStudy (anonymous):
alright thanks again
OpenStudy (anonymous):
Refer to the attachment from Mathematica.
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