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The double integral of f=(x^2+y^2), x from -1 to 2 and y from 0 to sqrt(4-x^2). I need to do this with integration in polar coordinates but I have no idea how to express the cutoff at x=-1. Help!
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draw it.
|dw:1381994393982:dw|
|dw:1381994480506:dw|
split into two integrals here.
\[ x=-1 \implies r\cos\theta = -1 \implies r=-\sec\theta \]
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Is it absolutely necessary to split this in to 2 integrals? If so then I know what I'm doing wrong. Is there a way to solve it using a single double integral?
You must split it up.
I see. Thanks for your help!
You have two \(r(\theta)\) function and I see no way of combining them nicely.
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