Question

Factor completely 5c^5 + 60c^4 + 180c^3.

5c^3(c + 6)(c - 6)

5c^3(c^2 + 12c + 36)

5c^3(c + 6)^2

5(c + 6)^2

Answer 1

@ganeshie8

Answer 2

I'm not sure what the GCF would be on this one

Answer 3

first look at numbers

Answer 4

5 , 60, 180

wats the gcf of these ?

Answer 5

I want to say 5

Answer 6

yup! pull that out first

Answer 7

because anything over 5 couldn't be a factor of 5 lol

Answer 8

5c^5 + 60c^4 + 180c^3

5(c^5 + 12c^4 + 36c^3)

Answer 9

fine ?

Answer 10

yeah

Answer 11

good, next look at c's
wats the GCF ?

Answer 12

c^3?

Answer 13

perfect ! pull that out also
wat do u get ?

Answer 14

5c^3(c^2 + 12c^1+ 36)

Answer 15

Yes !

Answer 16

:D

Answer 17

5c^3(c^2 + 12c^1+ 36)

is same as

5c^3(c^2 + 12c+ 36)

Answer 18

we're half done.
next, do u knw (a+b)^2 formula ?

Answer 19

umm not really

Answer 20

google and tell me :)

Answer 21

umm expanding formula?

Answer 22

yup

Answer 23

couldn't find much on it

Answer 24

here it is,
\(\large (a+b)^2 = a^2 + 2ab + b^2\)

Answer 25

now look at wat we have :-
5c^3(c^2 + 12c+ 36)

Answer 26

how can we use that formula here ?

Answer 27

uhh I'm not sure which one would be a or b if theres 3 numbers

Answer 28

let me show u how to do this completely :-

\(\large 5c^3(c^2 + 12c+ 36)\)

\(\large 5c^3(c^2 + 2*6*c+ 6^2)\)

\(\large 5c^3(c+6)^2\)

Answer 29

we're done.
see if that makes sense

Answer 30

Yeah I think I see it

Answer 31

good :)

below 3 identites are very useful, you better remember these for the rest of the course time :-

\(\large 1)~~~ (a+b)^2 = a^2+2ab + b^2 \)
\(\large 2)~~~ (a-b)^2 = a^2-2ab + b^2\)
\(\large 3)~~~ a^2-b^2 = (a+b)(a-b)\)

Answer 32

oly 3 formulas,
take time to memorize these. you should be able to call these at will and apply

Answer 33

Alright thanks man :)

Answer 34

np :)