There is NO one to one linear transformation $T: P_3\rightarrow M_{32}$ True or False. Explain
Please

Question

There is NO one to one linear transformation $T: P_3\rightarrow M_{32}$ True or False. Explain
Please

austinl · Answer

I'm sorry, but I don't really understand this at all. :(

austinl · Answer

Best of luck! Maybe amistre or someone knows?

loser66 · Answer

@amistre64

amistre64 · Answer

M(3x2) ?

loser66 · Answer

yes

amistre64 · Answer

$$P_3(x)=c_3x^3+c_2x^2+c_1x+c_0$$
$$M_{3x2}:\begin{vmatrix}m_{11}&m_{12}\m_{21}&m_{22}\m_{31}&m_{32}\end{vmatrix}$$

loser66 · Answer

first off, I want to confirm the definition of one-one function. Is it all image has preimage?

loser66 · Answer

or no need to have that direction? just all preimage has image?

amistre64 · Answer

one to one means that a unique preimage to image relation exists
the coefficent vector is a 4x1,  if A is a 3x4

amistre64 · Answer

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