Help please! A glider is released from rest with a spring stretched 0.100 m. What is the displacement, x, of the glider from its equilibrium position when its speed is 0.20 m/s?
x = 0.1 m v = 0.2 m/s do we know what the spring constant is from the the problem?
I believe it is 5.00 N/m
that works for me, so now we know: x = 0.1 m v = 0.2 m/s k = 5 n/m is there any other information, if not, this is a tough one!
the mass of the glider?
lets see; m=.200 kg aannndd I think that is it haha
and that is all we need! is your class studying kinematic equations, momentum or energy?
umm we just learned conservative energy
ok great, that is what we will use then -
okay :)
sorry, one last question, is the glider being shoot up into the air? or horizontal?
horizontal
so we will break this up in to events event 1 is when the glider is at rest event 2 is when the glider is traveling at a speed of .2 m/s
ummm okay
the energy equation will look like this: KE_spring = KE_spring + KE event 1 will have the values of V_1 = 0 m/s K = 5 n/m x = .1 can you remember the kinetic energy equations for KE and KE_spring
oh and event 1 is on the left of the = sign, and event 2 is on the right of the = sign, btw
isn't it 1/2mv^2 ?
or is it 1/2kx^2?
yep, and for a spring its (1/2) k x^2
if we exchange this equation KE_spring = KE_spring + KE for this equation (1/2) k x^2 = (1/2) k x^2 + (1/2)mv^2 we just now need to plug in what we know from event 1 and event 2 I'll give you a hint, the x on the left side = 0.1 and we are solving for the x on the right, so we have all the numbers to put in except the x on the right, can you give it a try? i'll draw a picture so it makes a bit more sense while you work on it
okay thank you! I will see what i get! :)
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brb
oh yay i got the right answer! thank you :) so the book says that there are going to be two answers for this problem. one negative and one positive. I don't understand why though?
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