Question

How can I solve, 125a^2 - 320

Answer 1

You want to solve of factor?

Answer 2

Solve for a? 125a^2 - 320 = 0

or

Factor 125a^2 - 320 = 0

Answer 3

I think I have to make it a binomial pair some how.

Answer 4

idk

Answer 5

leozap1....when you know what you have to do, you can repost your problem. I'm not going to second-guess your problem.

Answer 6

I have to make it a binomial pair like I said. -_-

Answer 7

You want to factor it.

Factor out what is common between 125a^2 and 320.

That's a 5.
5(25a^2 - 64)
And the 25a^2 - 64 is factorable into (5a-8)(5a+8)

Final answer: 5(5a-8)(5a+8)

Answer 8

Ok thank you.

Answer 9

welcome.

Answer 10

could you factorize something for me@Easyaspi314

Answer 11

(X-Y)^2-X+Y

Answer 12

Let's rewrite it as:

(x-y)^2 - (x-y)
So there's something in common between both of them, called (x-y)

So we pull out (x-y), and we get

(x-y)[(x-y) - 1]

Tricky problem, indeed.

Answer 13

i did try that... how did you arrive at that answer

Answer 14

I pulled out (factored) the (x-y) becuase (x-y) is common between both expressions

Answer 15

when that is expanded this is what i get

X^2 -2XY-X+Y^2+Y

Answer 16

should i be getting a -Y instead of a +Y

Answer 17

No, the way you typed your question is with a +Y

Answer 18

ohhh.... no wonder i wasnt getting it... silly me

Answer 19

thanks